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The adsorption energy is bonus?
Posted: Wed Jun 27, 2007 12:54 am
by lanjh
hellow!
I just calculated the adsorption energy of NH3 on Pt(111) surface/ But I found the adsorption energy is bonus~ This is of course a wrong results. Because others had done the same jobs, and obtained a value about -0.7eV.
The calculation was done as follows:
First, optimize the supercell of NH3 and Pt system.
Then, delete Nh3 from the above supercell. and optimized
At last, The NH3 was optimized with the same supercell
The three jobs was down with totally the same parameter.
Can anyone tell me where is the problem?
The adsorption energy is bonus?
Posted: Wed Jun 27, 2007 6:06 am
by lanjh
Sorry ,I have made a mistake. The calculated adsorption energy is not bonus. So I didn't not why. SOS
The adsorption energy is bonus?
Posted: Thu Jun 28, 2007 1:15 pm
by lanjh
Can anyone give me some advice?
The adsorption energy is bonus?
Posted: Thu Jun 28, 2007 2:26 pm
by lanjh
SYSTEM=Pt(111)_top
ENCUT=420
ENAUG=700
ISTART=0;ICHARG=2
ISMEAR=2; SIGMA=0.2
NSW=100
POTIM=0.3
IBRION=2
ALGO=V
GGA=91
EDIFF=1E-5
EDIFFG=-1E-2
PREC=Medium
LREAL=Auto
LWAVE=.FALSE.
Maybe I need provide more information. This is my INCAR.
The adsorption energy is bonus?
Posted: Mon Jul 02, 2007 8:01 am
by admin
please define what you mean by bonus . ..
--) do you take the balance correctly (final state - initial stae)
--) maybe the final state is a metastable state, not the equilibrium state of NH3 on Pt. Please check whether the geometry of that result is reasonable.
--) if NH3 is adsorbed on one surface only, you have to add dipole corrections
--) check whether ALGO=Fast gives the same results.
The adsorption energy is bonus?
Posted: Tue Jul 17, 2007 12:31 am
by lanjh
Sir, my problem still exists. Now I list my results .
For Pt/NH3 system, energy without entropy= -101.262864
For Pt slab, energy without entropy= -83.484689
For NH3 with the same box: energy without entropy= -19.084103
The parameters is as below: SYSTEM=Pt(111)_topa
ENCUT=420
ENAUG=700
ISTART=0;ICHARG=2
ISMEAR=2; SIGMA=0.2
NSW=100
POTIM=0.5
IBRION=2
ALGO=V
GGA=91
EDIFF=1E-5
EDIFFG=-1E-2
PREC=Accurate
LWAVE=.FALSE.
LCHARG=.FALSE.
#IDIPOL=3
When using the item ALGO=FAST,
energy without entropy= -101.261532
when the dipole corrections is considered,
energy without entropy= -100.878408
Now I am confused. I can check the geometry. The N-Surface distance in previous report is 2.16 A. In my calculation is 2.127. I thank the calculated structure is normal.
What is wrong with my work?
The adsorption energy is bonus?
Posted: Sat Jul 21, 2007 4:54 pm
by admin
are you sure that the adsorption site you considered is the most stable one?
The adsorption energy is bonus?
Posted: Wed Oct 17, 2007 6:21 am
by radny
Try this:
First, optimize the supercell of NH3/Pt adsorbed system.
Then, SEPARATE Nh3 from the substrate within the same supercell (the substrate should be a free, relaxed surface and the molecule like in a gas phase;)
Calculate the adsorption energy as E(adsorbed-system) - E(separated-system).
From our experience with VASP your method and the method just described give different results. I would like to know why. Any ideas?