Different in ground state energy (E0) from spin and non-spin polarized
Posted: Fri Jul 06, 2012 7:32 am
Hi Everyone,
I am a new VASP user. Currently I try to follow the VASP hands-on tutorial.
In the hands-on, the first two examples are oxygen atom without and with spin polarized respectively. I noticed that on the last line of the OZICAR file, the value E0 from non-spin and spin polarized systems are different. (E0 = -.16001392E+00 for non-spin and E0 = -.15948179E+01).
My question is which one is the most correct one?
Note: I try to investigate more on this issue by calculated the E0 for hydrogen atom. I've found that the calculation with spin polarized gives more correct answer; the ground state energy is very close to -13.6 eV from the analytical value of ground state of hydrogen atom. While the non-spin polarized calculation gives the value around -12.5 eV.
Thank you very much.
I am a new VASP user. Currently I try to follow the VASP hands-on tutorial.
In the hands-on, the first two examples are oxygen atom without and with spin polarized respectively. I noticed that on the last line of the OZICAR file, the value E0 from non-spin and spin polarized systems are different. (E0 = -.16001392E+00 for non-spin and E0 = -.15948179E+01).
My question is which one is the most correct one?
Note: I try to investigate more on this issue by calculated the E0 for hydrogen atom. I've found that the calculation with spin polarized gives more correct answer; the ground state energy is very close to -13.6 eV from the analytical value of ground state of hydrogen atom. While the non-spin polarized calculation gives the value around -12.5 eV.
Thank you very much.