LDOS
Posted: Mon Apr 24, 2006 10:51 am
Dear VASP-users,
I'm trying to calculate the LDOS for a system with one B-atom in a supercell with 128 Fe-atoms. using PAW-potentials. The Fe-atoms have 8 valence electrons each while the Boron atom usues 3 valence electrons. I've used LORBIT = 12 in order to avoid to specify the RWIGS-tag. When I sum up the individual LDOS in the OUTCAR-file I find that about 90 electrons are missing. As far as I understand there will be a loss from the interstitial regions, but is it reasonable that roughly 10 % isn't accounted for ?
The same thing happens if I put one single B-atom in a large supercell (10x10x10 A) and calculate the the LDOS with LORBIT=12. The LDOS then accounts for 1.6 of the 3 electrons. I've also used LORBIT=2 together with different RWIGS-values. Then I manage to increase th total charge accounted for up to 2.7 instead. I 'm now wondering if the LORBIT=12 is expected to produce these low values or if the reason may lie in the POTCAR-files used.
Best regards
Dan Fors
I'm trying to calculate the LDOS for a system with one B-atom in a supercell with 128 Fe-atoms. using PAW-potentials. The Fe-atoms have 8 valence electrons each while the Boron atom usues 3 valence electrons. I've used LORBIT = 12 in order to avoid to specify the RWIGS-tag. When I sum up the individual LDOS in the OUTCAR-file I find that about 90 electrons are missing. As far as I understand there will be a loss from the interstitial regions, but is it reasonable that roughly 10 % isn't accounted for ?
The same thing happens if I put one single B-atom in a large supercell (10x10x10 A) and calculate the the LDOS with LORBIT=12. The LDOS then accounts for 1.6 of the 3 electrons. I've also used LORBIT=2 together with different RWIGS-values. Then I manage to increase th total charge accounted for up to 2.7 instead. I 'm now wondering if the LORBIT=12 is expected to produce these low values or if the reason may lie in the POTCAR-files used.
Best regards
Dan Fors